(r^2+2r+2=0)^2

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Solution for (r^2+2r+2=0)^2 equation: 



(r^2+2r+2=0)^2

We move all terms to the left:

(r^2+2r+2-(0)^2)=0

We get rid of parentheses

r^2+2r+2-0^2=0

We add all the numbers together, and all the variables

r^2+2r+2=0

a = 1; b = 2; c = +2;
Δ = b2-4ac
Δ = 22-4·1·2
Δ = -4
Delta is less than zero, so there is no solution for the equation

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